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12,27,40,55-Tetratert-butyl-59,60,63,64-tetrathia-16,23,44,51-tetrazaundecacyclo[51.3.1.12,5.16,9.110,14.125,29.130,33.134,37.138,42.017,22.045,50]tetrahexaconta-1(56),2,4,6,8,10,12,14(62),15,23,25(61),26,28,30,32,34,36,38,40,42(58),43,51,53(57),54-tetracosaene-11,28,39,56-tetrol

更新时间:2025-09-07 13:15:01

12,27,40,55-Tetratert-butyl-59,60,63,64-tetrathia-16,23,44,51-tetrazaundecacyclo[51.3.1.12,5.16,9.110,14.125,29.130,33.134,37.138,42.017,22.045,50]tetrahexaconta-1(56),2,4,6,8,10,12,14(62),15,23,25(61),26,28,30,32,34,36,38,40,42(58),43,51,53(57),54-tetracosaene-11,28,39,56-tetrol结构式
12,27,40,55-Tetratert-butyl-59,60,63,64-tetrathia-16,23,44,51-tetrazaundecacyclo[51.3.1.12,5.16,9.110,14.125,29.130,33.134,37.138,42.017,22.045,50]tetrahexaconta-1(56),2,4,6,8,10,12,14(62),15,23,25(61),26,28,30,32,34,36,38,40,42(58),43,51,53(57),54-tetracosaene-11,28,39,56-tetrol结构式
委托求购
常用名 12,27,40,55-Tetratert-butyl-59,60,63,64-tetrathia-16,23,44,51-tetrazaundecacyclo[51.3.1.12,5.16,9.110,14.125,29.130,33.134,37.138,42.017,22.045,50]tetrahexaconta-1(56),2,4,6,8,10,12,14(62),15,23,25(61),26,28,30,32,34,36,38,40,42(58),43,51,53(57),54-tetracosaene-11,28,39,56-tetrol 英文名 12,27,40,55-Tetratert-butyl-59,60,63,64-tetrathia-16,23,44,51-tetrazaundecacyclo[51.3.1.12,5.16,9.110,14.125,29.130,33.134,37.138,42.017,22.045,50]tetrahexaconta-1(56),2,4,6,8,10,12,14(62),15,23,25(61),26,28,30,32,34,36,38,40,42(58),43,51,53(57),54-tetracosaene-11,28,39,56-tetrol
CAS号 1010101-84-4 分子量 1193.7
密度 N/A 沸点 N/A
分子式 C72H80N4O4S4 熔点 N/A
MSDS N/A 闪点 N/A

 名称

英文名 12,27,40,55-Tetratert-butyl-59,60,63,64-tetrathia-16,23,44,51-tetrazaundecacyclo[51.3.1.12,5.16,9.110,14.125,29.130,33.134,37.138,42.017,22.045,50]tetrahexaconta-1(56),2,4,6,8,10,12,14(62),15,23,25(61),26,28,30,32,34,36,38,40,42(58),43,51,53(57),54-tetracosaene-11,28,39,56-tetrol

 物理化学性质

分子式 C72H80N4O4S4
分子量 1193.7
InChIKey VGLLASLZJJWGRW-UHFFFAOYSA-N
SMILES CC(C)(C)c1cc2cc(c1O)-c1ccc(s1)-c1ccc(s1)-c1cc(cc(C(C)(C)C)c1O)C=NC1CCCCC1N=Cc1cc(c(O)c(C(C)(C)C)c1)-c1ccc(s1)-c1ccc(s1)-c1cc(cc(C(C)(C)C)c1O)C=NC1CCCCC1N=C2
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