N,5-bis(4-chlorophenyl)-3-propan-2-yliminophenazin-2-amine;[(7S,9E,11S,12R,13S,14R,15R,16R,17S,18S,19E,21Z)-2,15,17,32-tetrahydroxy-11-methoxy-3,7,12,14,16,18,22-heptamethyl-1'-(2-methylpropyl)-6,23-dioxospiro[8,33-dioxa-24,27,29-triazapentacyclo[23.6.1.14,7.05,31.026,30]tritriaconta-1(31),2,4,9,19,21,25(32),26,29-nonaene-28,4'-piperidine]-13-yl] acetate

N,5-bis(4-chlorophenyl)-3-propan-2-yliminophenazin-2-amine;[(7S,9E,11S,12R,13S,14R,15R,16R,17S,18S,19E,21Z)-2,15,17,32-tetrahydroxy-11-methoxy-3,7,12,14,16,18,22-heptamethyl-1'-(2-methylpropyl)-6,23-dioxospiro[8,33-dioxa-24,27,29-triazapentacyclo[23.6.1.14,7.05,31.026,30]tritriaconta-1(31),2,4,9,19,21,25(32),26,29-nonaene-28,4'-piperidine]-13-yl] acetate结构式

• 常用名: N,5-bis(4-chlorophenyl)-3-propan-2-yliminophenazin-2-amine;[(7S,9E,11S,12R,13S,14R,15R,16R,17S,18S,19E,21Z)-2,15,17,32-tetrahydroxy-11-methoxy-3,7,12,14,16,18,22-heptamethyl-1'-(2-methylpropyl)-6,23-dioxospiro[8,33-dioxa-24,27,29-triazapentacyclo[23.6.1.14,7.05,31.026,30]tritriaconta-1(31),2,4,9,19,21,25(32),26,29-nonaene-28,4'-piperidine]-13-yl] acetate
• 英文名: N,5-bis(4-chlorophenyl)-3-propan-2-yliminophenazin-2-amine;[(7S,9E,11S,12R,13S,14R,15R,16R,17S,18S,19E,21Z)-2,15,17,32-tetrahydroxy-11-methoxy-3,7,12,14,16,18,22-heptamethyl-1'-(2-methylpropyl)-6,23-dioxospiro[8,33-dioxa-24,27,29-triazapentacyclo[23.6.1.14,7.05,31.026,30]tritriaconta-1(31),2,4,9,19,21,25(32),26,29-nonaene-28,4'-piperidine]-13-yl] acetate
• CAS号: 134713-93-2
• 分子量: 1320.4
• 密度: N/A
• 沸点: N/A
• 分子式: C₇₃H₈₄Cl₂N₈O₁₁
• 熔点: N/A
• 闪点: N/A

名称

• 英文名: N,5-bis(4-chlorophenyl)-3-propan-2-yliminophenazin-2-amine;[(7S,9E,11S,12R,13S,14R,15R,16R,17S,18S,19E,21Z)-2,15,17,32-tetrahydroxy-11-methoxy-3,7,12,14,16,18,22-heptamethyl-1'-(2-methylpropyl)-6,23-dioxospiro[8,33-dioxa-24,27,29-triazapentacyclo[23.6.1.14,7.05,31.026,30]tritriaconta-1(31),2,4,9,19,21,25(32),26,29-nonaene-28,4'-piperidine]-13-yl] acetate

物理化学性质

• 分子式: C₇₃H₈₄Cl₂N₈O₁₁
• 分子量: 1320.4
• Smiles: CC(C)N=c1cc2n(-c3ccc(Cl)cc3)c3ccccc3nc-2cc1Nc1ccc(Cl)cc1.COC1C=COC2(C)Oc3c(C)c(O)c4c(O)c(c5c(c4c3C2=O)=NC2(CCN(CC(C)C)CC2)N=5)NC(=O)C(C)=CC=CC(C)C(O)C(C)C(O)C(C)C(OC(C)=O)C1C